I know the basic idea behind the constraint problems, and it's easy enough to figure this problem out even by hand using some of these techniques. However, formulating this together into a programming description is a little harder. This is a work in progress. The following code does it the brute force way, since this problem actually has a very small problem space.
∇Z←SOLVE;CHARS;SEND;MORE;MONEY;SEL  ⍝ Solve the send + more = money constraint problem.  ⍝ We have eight letters to work with:  CHARS←'demnorsy'  ⍝ We represent our three words as index vectors into  ⍝ CHARS  SEND←CHARS⍳'send'  MORE←CHARS⍳'more'  MONEY←CHARS⍳'money'  ⍝ Start with a matrix of the possible assignments  ⍝ to each of the eight letters, which is based on  ⍝ the permutations of the decimal digits.  SEL←(8⍴10)⊤∪10⊥¯1+⍉¯2↓PERM 10  ⍝ We remove any assignment that assigns  ⍝ S or M to 0, since these violate our constraints.  SEL←((0≠SEL[CHARS⍳'m';])^0≠SEL[CHARS⍳'s';])/SEL  ⍝ Now, we want to see which assignments for  ⍝ SEND and MORE, when added up, will be equivalent  ⍝ to the corresponding assignment to MONEY.  Z←((10⊥SEL[MONEY;])=(10⊥SEL[SEND;])+10⊥SEL[MORE;])/SEL  Z←⎕A[⎕a⍳CHARS]⍪1 8⍴Z ∇
 ⍝ Permutations by Ram Biyani
 Z←1 0⍴I←0
 T←(⍳I),(I-0 1)⍴(S⍴0,I⍴1)/S⍴⍳I
The above is about the simplest brute force method that I can figure out. I'd be interested in knowing about simpler brute force methods, and how I might actually represent a constraint problem like this inside of APL.